An isotope undergoes radioactive decay. The new isotope that forms has an atomic number that is 2 less than the original isotope’s.

Question

An isotope undergoes radioactive decay. The new isotope that forms has an atomic number that is 2 less than the original isotope’s.

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Thông Đạt 2 months 2021-07-30T01:37:04+00:00 1 Answers 3 views 0

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    2021-07-30T01:38:50+00:00

    Answer: The parent isotope is undergoing alpha decay.

    Explanation:

    A nuclear reaction is defined as the reaction in which the changes in the nucleus of an atom take place and usually form a different element. An unstable nucleus undergoes various decay processes to attain stability.

    Alpha decay is a type of decay process that happens when a heavy nucleus decays into a light nucleus with the release of an alpha particle. This alpha particle carries a charge of +2 units and has a mass of 4 units. It is also known as the helium nucleus. The general equation for this decay process is:

    X_Z^A\rightarrow Y_{Z-2}^{A-4}+\alpha _2^4

    It is given that the daughter isotope formed has atomic number 2 less than the parent isotope. Thus, it is undergoing alpha decay.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )