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An isosceles triangle has legs that are each `x` inches long and a base that is `y` inches long. The perimeter of this triangle is 38 inches
Question
An isosceles triangle has legs that are each `x` inches long and a base that is `y` inches long. The perimeter of this triangle is 38 inches. The base is 8 inches shorter than the length of a leg.
How long are the sides of the triangle?
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Mathematics
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2021-08-07T12:57:35+00:00
2021-08-07T12:57:35+00:00 1 Answers
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Answer:
15.333 inches
Step-by-step explanation:
First find the value of “y” which is the base and it is 8 inches shorter than the length legs of the triangle.
y = x – 8
Then substitute the values in the formula for the perimeter of an isosceles triangle.
Perimeter = 2 (L) + b
38 = 2 (x) + x – 8
38 = 2x + x – 8
38 = 3x – 8
38 + 8 = 3x
3x = 46
x = 15.333 inches
x is the length of the triangle and it’s actual value is 15.333 inches