An isosceles triangle has legs that are each `x` inches long and a base that is `y` inches long. The perimeter of this triangle is 38 inches

Question

An isosceles triangle has legs that are each `x` inches long and a base that is `y` inches long. The perimeter of this triangle is 38 inches. The base is 8 inches shorter than the length of a leg.

How long are the sides of the triangle?

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Nick 6 months 2021-08-07T12:57:35+00:00 1 Answers 4 views 0

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    2021-08-07T12:58:45+00:00

    Answer:

    15.333 inches

    Step-by-step explanation:

    First find the value of “y” which is the base and it is 8 inches shorter than the length legs of the triangle.

    y = x – 8

    Then substitute the values in the formula for the perimeter of an isosceles triangle.

    Perimeter = 2 (L) + b

    38 = 2 (x) + x – 8

    38 = 2x + x – 8

    38 = 3x – 8

    38 + 8 = 3x

    3x = 46

    x = 15.333 inches

    x is the length of the triangle and it’s actual value is 15.333 inches

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