An ice skater is spinning at 6.00 rev/s with his moment of inertia being 0.400 kg/m2. Calculate his new moment of inertia if he reduces his

Question

An ice skater is spinning at 6.00 rev/s with his moment of inertia being 0.400 kg/m2. Calculate his new moment of inertia if he reduces his rate of spin to 1.25 rev/s by extending his arms and increasing his moment of inertia.

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Orla Orla 6 days 2021-07-22T20:09:31+00:00 1 Answers 1 views 0

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    2021-07-22T20:10:31+00:00

    Answer:

    New moment of inertia will be I=1.92kgm^2

    Explanation:

    It is given initially angular velocity \omega =6rev/sec=6\times 2\pi =37.68rad/sec

    Moment of inertia I=0.4kgm^2

    Angular momentum is equal to L=I\omega =37.68\times 0.4=15.072kgm^2/sec

    Now angular velocity is decreases to \omega =1.25rev/sec=1.25\times 2\times 3.14=7.85rad/sec

    As we know that angular momentum is conserved

    So 15.072=I\times 7.85

    I=1.92kgm^2

    So new moment of inertia will be I=1.92kgm^2

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