An extremely long thin wire carries a uniform linear charge density of 358 nC/m. Find the potential difference between points 5.0 m and 6.0

Question

An extremely long thin wire carries a uniform linear charge density of 358 nC/m. Find the potential difference between points 5.0 m and 6.0 m from the wire, provided they are not near either end of the wire. (

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Gia Bảo 3 months 2021-07-28T14:58:53+00:00 1 Answers 21 views 0

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    2021-07-28T15:00:33+00:00

    Answer:

    1.2kV

    Explanation:

    We are given that

    Linear charge density,\lambda=358nC/m=358\times 10^{-9} C/m

    1 nC=10^{-9} C

    r_1=5 m

    r_2=6 m

    We have to find the potential difference between poinst 5.0 m and 6.0 m from the wire.

    We know that potential difference of wire

    V=2k\lambda ln\frac{r_2}{r_1}

    Where

    k=9\times 10^9

    Substitute the values

    V=2\times 9\times 10^9\times 358\times 10^{-9}ln\frac{6}{5}

    V=1174.8 V

    V=1.17 kV\approx 1.2 kV

    1kV=1000 V

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