. An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it go

Question

. An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station

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Thiên Hương 8 hours 2021-07-22T04:26:50+00:00 1 Answers 0 views 0

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    2021-07-22T04:27:51+00:00

    Answer:

    Explanation:

    Give it that,

    Initial velocity

    u = 22m/s

    Deceleration a = – 0.15m/s2

    Time taken to travel a station long of 210m

    Using equation of motion

    Let know the final velocity, when it leaves the station

    v² = u²+2as

    v² = 22²+2×(-0.15)×210

    v² = 484—63

    v² = 421

    v =√421

    v = 20.52m/s

    Then,

    Using equation of motion to find time taken

    v = u + at

    20.52 = 22 +(-0.15)t

    20.52-22 = -0.15t

    -0.15t = -1.48

    t = -1.48/-0.15

    t = 9.88 sec

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