An empirical formula calculation gives a molar ratio of 1.0 oxygen, 4.8 hydrogen, 4.1 carbon and 1.8 nitrogen. If the molecular mass is appr

Question

An empirical formula calculation gives a molar ratio of 1.0 oxygen, 4.8 hydrogen, 4.1 carbon and 1.8 nitrogen. If the molecular mass is approximately 200 amu, what is the molecular formula

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Xavia 5 months 2021-08-10T06:00:34+00:00 1 Answers 3 views 0

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    2021-08-10T06:01:34+00:00

    Answer:

    C_8H_{10}O_2N_4

    Explanation:

    Hello there!

    In this case, according to the given information about the empirical formula of this compound, we can infer that these mole ratios can be rounded to the following whole numbers in order to find the empirical formula:

    C_4H_5ON_2

    Whose molar mass is 97.09 amu and thus, the ratio of the molecular to the empirical molar mass is:

    200/97.09=2.1

    Which is almost a factor of 2; and therefore, the resulting molecular formula is:

    C_8H_{10}O_2N_4

    Regards!

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