## An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a

Question

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a distance d. (a) What is the magnitude of the electric field? (Use any variable or symbol stated above along with the following as necessary: e for the charge of the electron.)

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1 year 2021-08-23T19:49:57+00:00 1 Answers 154 views 0

$$E=\frac{K}{ed}$$

Explanation:

We are given that

Initial kinetic energy of an electron=K

Distance=d

Final velocity=v=0

Charge,q=-1e

We have to find the magnitude of electric field.

Work done=$$Force\times displacement$$

Using the formula

Work done=$$qE\times d=-eEd$$

Using work energy theorem

Work done=Final K.E-Initial K.E=0-K

Work done=-K

Substitute the values

-K=-eEd

K=eEd

$$E=\frac{K}{ed}$$

Hence, the magnitude of the electric field=$$E=\frac{K}{ed}$$