Share
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a
Question
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a distance d. (a) What is the magnitude of the electric field? (Use any variable or symbol stated above along with the following as necessary: e for the charge of the electron.)
in progress
0
Physics
1 year
2021-08-23T19:49:57+00:00
2021-08-23T19:49:57+00:00 1 Answers
154 views
0
Answers ( )
Answer:
[tex]E=\frac{K}{ed}[/tex]
Explanation:
We are given that
Initial kinetic energy of an electron=K
Distance=d
Final velocity=v=0
Charge,q=-1e
We have to find the magnitude of electric field.
Work done=[tex]Force\times displacement[/tex]
Using the formula
Work done=[tex]qE\times d=-eEd[/tex]
Using work energy theorem
Work done=Final K.E-Initial K.E=0-K
Work done=-K
Substitute the values
-K=-eEd
K=eEd
[tex]E=\frac{K}{ed}[/tex]
Hence, the magnitude of the electric field=[tex]E=\frac{K}{ed}[/tex]