An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a

Question

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a distance d. (a) What is the magnitude of the electric field? (Use any variable or symbol stated above along with the following as necessary: e for the charge of the electron.)

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Thạch Thảo 1 year 2021-08-23T19:49:57+00:00 1 Answers 154 views 0

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    2021-08-23T19:51:38+00:00

    Answer:

    [tex]E=\frac{K}{ed}[/tex]

    Explanation:

    We are given that

    Initial kinetic energy of an electron=K

    Distance=d

    Final velocity=v=0

    Charge,q=-1e

    We have to find the magnitude of electric field.

    Work done=[tex]Force\times displacement[/tex]

    Using the formula

    Work done=[tex]qE\times d=-eEd[/tex]

    Using work energy theorem

    Work done=Final K.E-Initial K.E=0-K

    Work done=-K

    Substitute the values

    -K=-eEd

    K=eEd

    [tex]E=\frac{K}{ed}[/tex]

    Hence, the magnitude of the electric field=[tex]E=\frac{K}{ed}[/tex]

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