An electron is placed 5.40 cm due north of a charged sphere and experienced a force of 8.30 x 10^-13 N due north. What is the electric field

Question

An electron is placed 5.40 cm due north of a charged sphere and experienced a force of 8.30 x 10^-13 N due north. What is the electric field experienced by the electron at that point?

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Dulcie 1 year 2021-08-23T12:25:34+00:00 1 Answers 7 views 0

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    2021-08-23T12:26:57+00:00

    Answer:

    The electric field is [tex]E = 5.1*10^6N/C.[/tex]

    Explanation:

    The force [tex]F[/tex] on a charge [tex]q[/tex] in an electric field [tex]E[/tex] is given by

    [tex]F = qE[/tex],

    which can be rearranged to give

    [tex]E = \dfrac{F}{q }[/tex]

    Now, the force on the electron is [tex]F = 8.30*10^{-13}N[/tex], and its charge is

    [tex]q = 1.6*10^{-19}C[/tex]; therefore,

    [tex]E = \dfrac{8.30*10^{-13}N}{1.6*10^{-19}C}[/tex]

    [tex]\boxed{E = 5.1*10^6N/C}[/tex]

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