An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which

Question

An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C. (a) What is the speed of the electron 1.3 ns after entering this region? (b) How far does the electron travel during the 1.3 ns interval?

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Eirian 1 week 2021-07-22T15:06:56+00:00 1 Answers 8 views 0

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    2021-07-22T15:08:53+00:00

    Answer:

    1.) 11 km/s

    2.) 9.03 × 10^-5 metres

    Explanation:

    Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

    Electron q = 1.6×10^-19 C

    Electron mass = 9.11×10^-31 Kg

    (a) What is the speed of the electron 1.3 ns after entering this region?

    E = F/q

    F = Eq

    Ma = Eq

    M × V/t = Eq

    Substitute all the parameters into the formula

    9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

    V = 7.68×10^-18 /7.0×10^-22

    V = 10971.43 m/s

    V = 11 Km/s approximately

    (b) How far does the electron travel during the 1.3 ns interval?

    The initial velocity U = 64 km/s

    S = ut + 1/2at^2

    S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

    S =8.32×10^-5 + 7.13×10^-6

    S = 9.03 × 10^-5 metres

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