An electromagnet produces a magnetic field of 0.550 T in a cylindrical region of radius 2.50 cm between its poles. A straight wire carrying

Question

An electromagnet produces a magnetic field of 0.550 T in a cylindrical region of radius 2.50 cm between its poles. A straight wire carrying a current of 10.8 A passes through the center of this region and is perpendicular to both the axis of the cylindrical region and the magnetic field. What magnitude of force does this field exert on the wire?

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niczorrrr 5 months 2021-08-15T00:38:13+00:00 1 Answers 10 views 0

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    2021-08-15T00:39:37+00:00

    Answer: 0.297N

    Explanation:

    B = 0.550T

    r = 2.50cm = 0.025m

    I = 10.8A

    L = 2r = 2* 0.025 = 0.050m

    ¤(theta) = 90°

    Magnitude of the force (F) = BIL Sin ¤

    F = 0.550 * 10.8 * 0.050 * sin 90

    F = 0.550 * 10.8 * 0.050 * 1

    F = 0.297N

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