An electric iron consumes energy at a rate of 840 W when heating is at the maximum rate and 360 W when the heating is at the minimum. The v

Question

An electric iron consumes energy at a rate of 840 W when heating is at the maximum rate and 360 W when the heating is at the minimum. The voltage is 220 V. What are the current and the resistance in each case?

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Mít Mít 3 months 2021-08-25T17:01:24+00:00 1 Answers 0 views 0

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    2021-08-25T17:02:55+00:00

    Answer:

    At maximum  the  current is 4A and resistance is 55Ω

    At minimum the current is 1.636A and resistance is 134.45Ω

    Explanation:

    The computation of the current and the resistance in each case is shown below:

    At the time when it is heated at max rate,

    power, P = 840W

    V = 220V

    As We know that

    P = VI

    840 = 220 × I

    I = 840 ÷ 220

    I = 4 A

    Now

    R = V ÷ I

    = 220 ÷4

    = 55 Ω


    Hence, the  current is 4A and resistance is 55Ω

    At the time When it is heated at minimum rate,

    power, P = 360W

    V = 220V

    As We know that

    P = VI

    360 = 220 × I

    I = 360 ÷ 220

    I = 1.636 A

    Now

    R = V÷ I

    = 220 ÷1.636

    = 134.45 Ω


    Hence, the current is 1.636A and resistance is 134.45Ω

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