## An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m long and has a

Question

An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m long and has a resistance R of 0.126 Ohm. The outer surface temperature Tw is held at 422.1 K. The average thermal conductivity is K = 22.5 W/mK. Calculate the center temperature. Power = I^2R (Watts) Where I = current in nmps and R = Resistance in ohms I^2R (Watts) = q pi(Radius)^2L

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2 months 2021-07-26T18:12:28+00:00 1 Answers 13 views 0

The value is Explanation:

From the question we are told that

The  current is The radius is The  length of the wire is \

The  resistance is The  outer surface temperature is The average thermal conductivity is Generally the heat generated in the stainless steel wire is mathematically represented as  => => Generally the middle temperature is mathematically represented as   