Share
An elastic band with a spring constant of 62 N/m is extended by 0.15 m. What is the force applied to the rubber band?
Question
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Answers ( )
Answer:
the force applied to the rubber band is -9.3N
Explanation:
The computation of the force applied to the rubber band is shown below;
We know that
Force in newtons = Spring constant × amount of extension
F = -k × x
where
-k = 62 N/m
And, x = 0.15m
So, the force applied is
= -62N/m × 0.15m
= -9.3N
hence, the force applied to the rubber band is -9.3N
the force applied to the rubber band is -9.3N
Explanation: