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## An elastic band with a spring constant of 62 N/m is extended by 0.15 m. What is the force applied to the rubber band?

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## Answers ( )

Answer:the force applied to the rubber band is -9.3NExplanation:The computation of the force applied to the rubber band is shown below;

We know that

Force in newtons = Spring constant × amount of extension

F = -k × x

where

-k = 62 N/m

And, x = 0.15m

So, the force applied is

= -62N/m × 0.15m

= -9.3N

hence,

the force applied to the rubber band is -9.3Nthe force applied to the rubber band is -9.3N

Explanation: