an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per second. The radi

Question

an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per second. The radius of the hammer’s path is 2.0 meters.

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Hưng Khoa 3 years 2021-08-22T13:41:47+00:00 1 Answers 527 views 0

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    2021-08-22T13:43:32+00:00

    Answer:

    ac = 72 m/s²

    Fc = 504 N

    Explanation:

    We can find the centripetal acceleration of the hammer by using the following formula:

    a_c = \frac{v^2}{r}

    where,

    ac = centripetal acceleration = ?

    v = constant speed = 12 m/s

    r = radius = 2 m

    Therefore,

    a_c = \frac{(12\ m/s)^2}{2\ m}

    ac = 72 m/s²

    Now, the centripetal force applied by the athlete on the hammer will be:

    F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)

    Fc = 504 N

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