An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reaches the groun

Question

An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reaches the ground 10s after it is thrown the atmosphere of Planet X has a negligible effect on the rock. Determined the acceleration due to gravity of the rock when it is in planet x

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Nem 6 months 2021-08-09T16:46:34+00:00 1 Answers 5 views 0

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    2021-08-09T16:47:58+00:00

    Answer:5 m/s^{2}

    Explanation:

    This problem is related to vertical motion, and the equation that models it is:

    y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

    Where:

    y=0m is the rock’s final height

    y_{o}=100 m is the rock’s initial height

    V_{o}=15 m/s is the rock’s initial velocity

    \theta=90\° is the angle at which the rock was thrown (directly upwards)

    t=10 s is the time

    g is the acceleration due gravity in Planet X

    Isolating g and taking into account sin(90\°)=1 :

    g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

    g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

    g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

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