An article in Human Factors (June 1989) presented data on visual accommodation (a function of eye movement) when recognizing a speckle patte

Question

An article in Human Factors (June 1989) presented data on visual accommodation (a function of eye movement) when recognizing a speckle pattern on a high-resolution CRT screen. The data are as follows: 36.45, 67.90, 38.77, 42.18, 26.72, 50.77, 38.9, and 50.06. Calculate the sample mean and sample standard deviation.

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Diễm Kiều 3 years 2021-08-05T23:40:05+00:00 1 Answers 25 views 0

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  1. thienthanh
    0
    2021-08-05T23:41:35+00:00
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    Answer:

    Mean = 43.969

    Standard deviation = 12.341

    Step-by-step explanation:

    Given the data :

    36.45, 67.90, 38.77, 42.18, 26.72, 50.77, 38.9, 50.06

    The sample mean :

    Σx / n = 351.75 / 8 = 43.969

    Sample standard deviation :

    √Σ(x – mean)²/n-1

    √[(36.45-43.969)² + (67.90-43.969)² + (38.77-43.969)² + (42.18-43.969)² + (26.72-43.969)² + (50.77-43.969)² + (38.9-43.969)² + (50.06-43.969)² ] / ((8 – 1)

    Standard deviation = 12.341

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