An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If you paired th

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An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If you paired them up, what fraction of the protons would have no electrons

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RobertKer 6 months 2021-07-14T06:49:17+00:00 1 Answers 26 views 0

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    2021-07-14T06:50:33+00:00

    Answer:

    The fraction of the protons would have no electrons =1.88\times 10^{-10}

    Explanation:

    We are given that

    Amoeba has total number of protons=1.00\times 10^{16}

    Net charge, Q=0.300pC

    Electrons are fewer than protons=1.88\times 10^6

    We have to find the fraction of protons would have no electrons.

    The fraction of the protons would have no electrons

    =\frac{Fewer\;electrons}{Total\;protons}

    The fraction of the protons would have no electrons

    =\frac{1.88\times 10^{6}}{1.00\times 10^{16}}

    =1.88\times 10^{-10}

    Hence, the fraction of the protons would have no electrons =1.88\times 10^{-10}

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