## An aluminum “12 gauge” wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field

Question

An aluminum “12 gauge” wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds.

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5 months 2021-09-01T10:51:03+00:00 1 Answers 0 views 0

1. Complete Question

An aluminum “12 gauge” wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds.

I = 1.2 A at time 5 secs.

Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 seconds.

The charge is Explanation:

From the question we are told that

The diameter of the wire is The radius of  the wire is The resistivity of aluminum is The electric field change is mathematically defied as Generally the charge is  mathematically represented as Where A is the area which is mathematically represented as So Therefore substituting values  From the question we are told that t =  5 sec   