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An airplane accelerates from a velocity of 24.96 m/s at a constant rate of 4.39 m/s2 over 564.00 m. What is its final velocity?
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Answers ( )
Answer:
74.7 m/s
Explanation:
Given:
Δx = 564.00 m
v₀ = 24.96 m/s
a = 4.39 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (24.96 m/s)² + 2 (4.39 m/s²) (564.00 m)
v = 74.7 m/s