An aircraft performs a maneuver called an “aileron roll.” During this maneuver, the plane turns like a screw as it maintains a straight flig

Question

An aircraft performs a maneuver called an “aileron roll.” During this maneuver, the plane turns like a screw as it maintains a straight flight path, which sets the wings in circular motion. If it takes it 36 s to complete the circle and the wingspan of the plane is 14.2 m, what is the acceleration of the wing tip

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Huyền Thanh 2 months 2021-08-17T02:07:09+00:00 1 Answers 24 views 0

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    2021-08-17T02:08:52+00:00

    Answer:

    The acceleration of the wing tip is 0.216 m/s²

    Explanation:

    Given;

    time to complete on circle, t = 36 s

    the wingspan of the plane = 14.2 m, this is equal to diameter of the circle, thus radius of the circle, r = ¹/₂ x 14.2 = 7.1 m

    distance of a complete circle = circumference of a circle = 2πr

    circumference of a circle = 2πr = 2π x 7.1 = 44.6164 m

    velocity, v = distance / time

    velocity of the wing tip, v = 44.6164 / 36

                                              = 1.239 m/s

    Centripetal acceleration of the wing tip = v²/r

                                                                      = (1.239²)/7.1

                                                                      = 0.216 m/s²

    Therefore, the acceleration of the wing tip is 0.216 m/s²

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