An 80kg student running at 3.50m/s grabs a rope that is hanging vertically. How high will the student swing?

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An 80kg student running at 3.50m/s grabs a rope that is hanging vertically. How high will the student swing?

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Thiên Ân 3 years 2021-07-29T19:20:09+00:00 1 Answers 30 views 0

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    2021-07-29T19:21:34+00:00

    Answer:

    The student will swing to a height of 61.25 cm.

    Explanation:

    Given that,

    Mass of the student, m = 80 kg

    Speed of student, v = 3.5 m/s

    The student running at this speed grabs a rope that is hanging vertically. In the whole process, the energy of the system remains conserved. So, using conservation of energy to find the height reached by the student. So,

    \dfrac{1}{2}mv^2=mgh

    h is height reached by the student

    h=\dfrac{v^2}{2g}\\\\h=\dfrac{(3.5)^2}{2\times 10}\\\\h=0.6125\ m\\\\h=61.25\ cm

    So, the student will swing to a height of 61.25 cm.

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