An 3-kg object is dropped from a height of 5 m. The rock has an impact speed of

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An 3-kg object is dropped from a height of 5 m. The rock has an impact speed

of

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  1. Answer:

    The rock has an impact speed  of 9.9 m/s.

    Explanation:

    given information:

    object’s mass, m = 3 kg

    height, h = 5 m

    in this case, the potential energy is equal to the kinetic energy

    PE = KE

    mgh = [tex]\frac{1}{2}[/tex] mv²

    where

    m = mass (kg)

    g = gravitational constant (9.8 m/s²)

    v = velocity (m/s)

    so,

    mgh = [tex]\frac{1}{2}[/tex] mv²

    gh = [tex]\frac{1}{2}[/tex] v²

    v² = 2gh

    v = √2gh

      = √(2)(9.8)(5)

      = 9.9 m/s

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