An 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.5-T magnetic field. The loop is rotated so that its plane is par

Question

An 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.5-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.20 s. What is the average induced emf in the loop?

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RI SƠ 6 months 2021-07-29T02:52:25+00:00 1 Answers 22 views 0

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    2021-07-29T02:53:51+00:00

    Answer:

    The average induced emf in the loop is 0.20 V

    Explanation:

    Given:

    Radius of loop r = \frac{d}{2} = 9.25 \times 10^{-2} m

    Magnetic field B = 1.5 T

    Change in time \Delta t = 0.20 sec

    According to the faraday’s law,

    Induced emf is given by

        \epsilon = -\frac{\Delta \phi}{\Delta t}

    Where \phi = magnetic flux

      \phi = BA\cos0                                ( here \theta = 0 )      

    Where A = \pi r^{2}

    We neglect minus sign because it’s shows lenz law

       \epsilon  = \frac{B \pi r^{2}  }{\Delta t}

       \epsilon = \frac{1.5 \times 3.14 \times (9.25 \times 10^{-2} )^{2} }{0.20}

       \epsilon = 0.20 V

    Therefore, the average induced emf in the loop is 0.20 V

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