An 11.5 mL portion of 0.162 M H3PO4 (aq) is to be titrated with 0.229 M NaOH (aq). What volume (in mL) of NaOH will it take to reach the equ

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An 11.5 mL portion of 0.162 M H3PO4 (aq) is to be titrated with 0.229 M NaOH (aq). What volume (in mL) of NaOH will it take to reach the equivalence point

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Verity 6 months 2021-07-22T02:00:32+00:00 1 Answers 4 views 0

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    2021-07-22T02:02:05+00:00

    Answer:

    8.14 mL of NaOH are required to reach the equivalence point.

    Explanation:

    Formula for titration is

    mmoles of base = mmoles of acid.

    Equality is fullfilled at the equivalence point.

    M of acid . volume of acid = M of base . volume of base

    Let’s replace with data given:

    11.5 mL . 0.162M = 0.229 M . volume of base

    Volume of base = (11.5 mL . 0.162M ) / 0.229M

    Volume of base = 8.14 mL

    8.14 mL of NaOH are required to reach the equivalence point.

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