Americium-241 is widely used in smoke detectors. The radiation released by this element ionizes particles that are then detected by a charge

Question

Americium-241 is widely used in smoke detectors. The radiation released by this element ionizes particles that are then detected by a charged-particle collector. The half-life of 241Am is 432 years, and it decays by emitting alpha particles. How many alpha particles are emitted each second by a 5.54-g sample of 241Am

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Edana Edana 2 months 2021-07-23T13:24:23+00:00 1 Answers 5 views 0

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    2021-07-23T13:26:20+00:00

    Answer:

    Explanation:

    Half life T is 432 years .

    432 years = 432 x 365 x 24 x 60 x 60 s

    = 1.36 x 10¹⁰ s .

    No of atoms in 5.54 g of sample of Am N= 6.02 x 10²³ x 5.54 / 241

    N = 138.38 x 10²⁰ atoms .

    disintegration constant λ = .693 / half life

    λ =  .693 / 1.36 x 10¹⁰ s .

    = .51 x 10⁻¹⁰ .

    dN / dt = λN

    = .51 x 10⁻¹⁰  x  138.38 x 10²⁰

    = 70.57 x 10¹⁰ per second.

    No of particles emitted = no of disintegration per second

    No of particles emitted =  70.57 x 10¹⁰ per second.

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