## ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. In working this probl

Question

ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are
measurements.
In working this problem, assume the value of “g” to be 9.8 m/s2 with two (2) significant digits unless
otherwise stated.
A mass of 2700 kg is raised 2.0 m in 10 seconds. What is the potential energy of the mass at this height?

A.39,000
B.3,900
C.0

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3 weeks 2021-08-23T22:53:09+00:00 1 Answers 0 views 0

52920 Joules

Explanation:

This is a case of gravitational potential energy…

We can apply the equation for gravitational energy as P = mgh, where m = mass of object, g = acceleration due to gravity, h = height. Let us substitute the known values into this formula and solve for P, the potential energy.

_______________________________________________________

The mass of the object is given to be 2700 kg, raised to a height of 2.0 meters. The time is not needed in this case, but we know that the acceleration due to gravity is a constant – 9.8 m / s,

P = ( 2700 kg )( 9.8 m / s )( 2 m ),

P = 52920

This doesn’t match the given options, so please let me know if you have the right question / options at hand.