Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the same time b

Question

Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the same time by pushing on box A with a horizontal pushing force FP = 8.9 N. Here, A has a mass mA = 10.2 kg and B has a mass mB = 7.0 kg. The contact force between the two boxes is FC. The coefficient of kinetic friction between the boxes and the floor is 0.04. (Assume FP acts in the +x direction.)

in progress 0
RuslanHeatt 1 year 2021-09-03T14:53:15+00:00 1 Answers 68 views 0

Answers ( )

    0
    2021-09-03T14:54:28+00:00

    Answer:

    Explanation:

    The force of friction acting on the system

    = .04 x 9.8 ( 10.2 + 7 )

    = 6.74 N

    Net force = 8.9 – 6.74

    = 2.16 N

    Acceleration in the system

    = 2.16 /  ( 10.2 + 7 )

    = .12558 m / s ²

    Contact force between boxes = FP

    Considering force on box A

    Net force = 8.9 – FP

    Applying Newton’s law on box A

    8.9 – FP = 10.2 x .12558

    = 1.28

    FP = 8.9 – 1.28

    = 7.62 N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )