Air is about 78.0% nitrogen molecules and 21.0% oxygen molecules. Several other gases make up the remaining 1% of air molecules. Part

Question

Air is about 78.0% nitrogen molecules and 21.0% oxygen molecules. Several other gases make up the remaining 1% of air molecules.
Part A
What is the partial pressure of nitrogen in air at atmospheric pressure (1 atm)? Assume ideal behavior.
Express your answer to three significant figures and include the appropriate units.
Part B
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Part C
What is the partial pressure of oxygen in air at atmospheric pressure (1 atm)? Assume ideal behavior.
Express your answer to two decimal places and include the appropriate units.

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Maris 1 day 2021-07-21T05:32:48+00:00 1 Answers 0 views 0

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    2021-07-21T05:34:30+00:00

    Answer:

    For A: The partial pressure of nitrogen in air is 0.780 atm

    For C: The partial pressure of oxygen in air is 0.210 atm

    Explanation:

    Raoult’s law is the law that is used to calculate the partial pressure of the individual gases present in the mixture.

    The equation for Raoult’s law is given as:

    p_A=\chi_A\times p_T                  …..(1)

    where,

    p_A = partial pressure of component A in the mixture

    p_T = total partial pressure of the mixture

    \chi_A = mole fraction of A

    • For A:

    We are given:

    % composition of nitrogen in air = 78.0 %

    \chi_{N_2}=0.780\\\\p_T=1atm

    Putting values in equation 1, we get:

    p_{N_2}=0.780\times 1atm\\\\p_{N_2}=0.780atm

    Hence, the partial pressure of nitrogen in air is 0.780 atm

    • For C:

    We are given:

    % composition of oxygen in air = 21.0 %

    \chi_{O_2}=0.210\\\\p_T=1atm

    Putting values in equation 1, we get:

    p_{O_2}=0.210\times 1atm\\\\p_{O_2}=0.210atm

    Hence, the partial pressure of oxygen in air is 0.210 atm

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