Ai giúp em với!!!!!! Tìm x ạ Question Ai giúp em với!!!!!! Tìm x ạ in progress 0 Môn Toán Ladonna 4 years 2020-11-27T01:08:59+00:00 2020-11-27T01:08:59+00:00 2 Answers 50 views 0
Answers ( )
Đáp án:
Giải thích các bước giải:
$b) (2x-3)^{2}=9$
$⇔$\(\left[ \begin{array}{l}(2x-3)^{2}=3^{2}\\(2x-3)^{2}=(-3)^{2}\end{array} \right.\)
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$⇔$\(\left[ \begin{array}{l}2x-3=3\\2x-3=-3\end{array} \right.\)
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$⇔$\(\left[ \begin{array}{l}2x=6\\2x=0\end{array} \right.\)
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$⇔$\(\left[ \begin{array}{l}x=3\\x=0\end{array} \right.\)
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$c) (x-\dfrac{1}{3})^{2}=\dfrac{1}{25}$
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$⇔$\(\left[ \begin{array}{l}x-\frac{1}{3}=\frac{1}{5}\\x-\frac{1}{3}=\frac{-1}{5}\end{array} \right.\)
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$⇔$\(\left[ \begin{array}{l}x=\frac{8}{15}\\x=\frac{2}{15}\end{array} \right.\)
`b)(2x-3)^2=9`
`(2x-3)^2=3^2`
`2x-3=3`
`2x=6`
`x=3`
`c)(x-1/3)^2=1/25`
`(x-1/3)^2=(1/5)^2`
`x-1/3=1/5`
`x=8/15`