After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm . She finds that the pendulum makes 1

Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm . She finds that the pendulum makes 100 complete swings in a time of 130 s . What is the value of g on this planet?

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2 years 2021-07-21T06:20:05+00:00 1 Answers 9 views 0

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    2021-07-21T06:21:19+00:00

    Explanation:

    Given:

    l = 55.0 cm = 0.550 m

    T = (130 s)/100 = 1.30 s

    g = ?

    The period of a pendulum is given by

    [tex]T=2 \pi \sqrt{ \dfrac{l}{g}}[/tex]

    Solving for T, we get

    [tex]\dfrac{T^2}{4 \pi^2}=\dfrac{l}{g}[/tex]

    Solving for g, we get

    [tex]g=\dfrac{4 \pi^2l}{T^2}=\dfrac{4 \pi^2(0.550 m)}{(1.30\:s)^2}=12.8\:\dfrac{m}{s^2}[/tex]

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