After a 4.626g sample of silver oxide is heated, 4.306g of silver metal remains. What is the empirical formula of the compound? pleas

by

After a 4.626g sample of silver oxide is heated, 4.306g of silver metal remains. What is the empirical formula of the compound?
please help me 🙁

0 thoughts on “After a 4.626g sample of silver oxide is heated, 4.306g of silver metal remains. What is the empirical formula of the compound? pleas”

  1. Answer:

    Hello There!!

    Explanation:

    The answer is↬The empirical formula is Ag2O. It is the simplest whole-number ratio of atoms in a compound.

    hope this helps,have a great day!!

    ~Pinky~

    Reply

  2. Answer:

    The empirical formula is Ag2O.

    The empirical formula is Ag2O.Explanation:

    The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.

    The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to 2O.

    do the steps ...

    To get this into an integer ratio, we divide both numbers by the smaller value.

    From this point on, I like to summarize the calculations in a table.

    ElementAgMass/gXMolesXllRatiomllIntegers

    mAgXXXm7.96Xm0.07377Xll2.00mmm2

    mlOXXXXl0.59mm0.0369Xml1mmmml1

    There are 2 mol of Ag for 1 mol of O.

    Reply

Leave a Comment