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According to Coulomb’s law, when the distance between two point charges doubles, what happens to the electric force acting between the charg
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Answer:
If the distance between charges is doubled, then the Force will become one-fourth.
F’ = F/4
Explanation:
The Coulomb’s Law gives the relation for the attractive or repulsive forces between two charges. The relation or formula is given as follows:
F = kq₁q₂/r²
where,
F = Attractive or Repulsive forces between the charges
k = Coulomb’s Constant
q₁ = magnitude of 1st charge
q₂ = magnitude of 2nd charge
r = distance between charges
If we keep the magnitude of charges constant then the relation between Force an Distance between charges will be:
F α 1/r²
So, it is clear from this relation that if the distance between charges is doubled, then the Force will become one-fourth.
F’ = F/4