According to Coulomb’s law, if the separation between two particles of the same charge increases four times, the potential energy of the two

Question

According to Coulomb’s law, if the separation between two particles of the same charge increases four times, the potential energy of the two particles:__________.
a. is one-sixteenth as high as it was before the separation.
b. is four times as high as it was before the distance separation.
c. is one-fourth as high as it was before the separation.
d. does not change.

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Neala 4 years 2021-07-17T20:10:42+00:00 1 Answers 34 views 0

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  1. thongdat2
    0
    2021-07-17T20:11:50+00:00
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    Answer:

    c.   V = k Q1 * Q2 / R1      potential energy of Q1 and Q2 separated by R

    V2 / V1 = (R1 / R2) = 1/4

    V2 = V1 / 4

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