A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of the wire and

Question

A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of the wire and the current I through it if the wire has the following resistances?
a) 1.0Ω
b) 2.0Ω
c) 3.0Ω

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Nick 2 months 2021-08-31T14:32:32+00:00 1 Answers 0 views 0

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    2021-08-31T14:33:41+00:00

    Answer:

    Potential difference = 6.0 V

    I for 1.0Ω = 6 A

    I for 2.0Ω = 3 A

    I for 3.0Ω = 2 A

    Explanation:

    Potential difference (ΔV) = Current (I) x Resistance (R)

    The potential difference is constant and equals 6.0 V, hence;

    I = ΔV/R

    When R = 1.0, I =6/1 = 6 amperes

    When R = 2.0, I = 6/2 = 3 amperes

    When R = 3.0, I = 6/3 = 2 amperes

    The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.

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