Share

## A wire of uniform cross-section is stretched along a meter stick, and a potential difference of 0.3 V is maintained between the 51 cm and 62

Question

A wire of uniform cross-section is stretched along a meter stick, and a potential difference of 0.3 V is maintained between the 51 cm and 62 cm marks. How far apart on the wire are two points that differ in potential by 112 mV ? Answer in units of cm.

in progress
0

Physics
1 year
2021-07-26T21:58:37+00:00
2021-07-26T21:58:37+00:00 1 Answers
107 views
0
## Answers ( )

Answer:[tex]l_{2} = 4106 \times 10^{-3} = 4.1 cm[/tex]

Explanation:GIVEN

potential difference = 0.3 V

and given length = 62 -51 = 11 cm

questionhow far apart on the wire are two points that differ in potential by 112 m V?

potential difference = 112 m V

by using formula [tex]V \alpha l[/tex]

[tex]\frac{V_{1}}{V_{2}} = \frac{l_{1}}{l_{2}}[/tex]

[tex]l_{2} =?[/tex]

[tex]l_{2} = \frac{V_2}{V_{1}} l_{1}[/tex]

put the values we get

[tex]l_{2} = 4106 \times 10^{-3} = 4.1 cm[/tex]