# A wire of uniform cross-section is stretched along a meter stick, and a potential difference of 0.3 V is maintained between the 51 cm and 62

Question

A wire of uniform cross-section is stretched along a meter stick, and a potential difference of 0.3 V is maintained between the 51 cm and 62 cm marks. How far apart on the wire are two points that differ in potential by 112 mV ? Answer in units of cm.

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2 years 2021-07-26T21:58:37+00:00 1 Answers 107 views 0

$$l_{2} = 4106 \times 10^{-3} = 4.1 cm$$

Explanation:

GIVEN

potential difference  = 0.3 V

and given length =  62 -51 = 11 cm

question

how far apart on the wire are two points that differ in potential by 112 m V?

potential difference = 112 m V

by using formula $$V \alpha l$$

$$\frac{V_{1}}{V_{2}} = \frac{l_{1}}{l_{2}}$$

$$l_{2} =?$$

$$l_{2} = \frac{V_2}{V_{1}} l_{1}$$

put the values we get

$$l_{2} = 4106 \times 10^{-3} = 4.1 cm$$