A wire of uniform cross-section is stretched along a meter stick, and a potential difference of 0.3 V is maintained between the 51 cm and 62

Question

A wire of uniform cross-section is stretched along a meter stick, and a potential difference of 0.3 V is maintained between the 51 cm and 62 cm marks. How far apart on the wire are two points that differ in potential by 112 mV ? Answer in units of cm.

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Nick 1 year 2021-07-26T21:58:37+00:00 1 Answers 107 views 0

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    2021-07-26T22:00:29+00:00

    Answer:

    [tex]l_{2} = 4106 \times 10^{-3} = 4.1 cm[/tex]

    Explanation:

    GIVEN

    potential difference  = 0.3 V

    and given length =  62 -51 = 11 cm

    question

    how far apart on the wire are two points that differ in potential by 112 m V?

    potential difference = 112 m V

    by using formula [tex]V \alpha l[/tex]

    [tex]\frac{V_{1}}{V_{2}} = \frac{l_{1}}{l_{2}}[/tex]

    [tex]l_{2} =?[/tex]

    [tex]l_{2} = \frac{V_2}{V_{1}} l_{1}[/tex]

    put the values we get

    [tex]l_{2} = 4106 \times 10^{-3} = 4.1 cm[/tex]

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