A wire carries a current of 0.76 A. This wire makes an angle of 46° with respect to a magnetic field of magnitude 6.0 × 10-5 T. The wire exp

Question

A wire carries a current of 0.76 A. This wire makes an angle of 46° with respect to a magnetic field of magnitude 6.0 × 10-5 T. The wire experiences a magnetic force of magnitude 9.4 × 10-5 N. What is the length of the wire?

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Xavia 2 months 2021-07-29T10:58:01+00:00 1 Answers 1 views 0

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    2021-07-29T10:59:29+00:00

    Answer:

    The length of the wire is 2.86 m

    Explanation:

    Given:

    Current I = 0.76 A

    Magnetic field B = 6 \times 10^{-5} T

    Force F = 9.4 \times 10^{-5} N

    Angle between wire and magnetic field \theta = 46°

    The magnetic force on the current carrying wire is given by,

      F = BIl\sin \theta

    Where l = length of wire

       l = \frac{F}{BI \sin 46}

       l = \frac{9.4 \times 10^{-5} }{6 \times 10^{-5}\times  0.76 \times 0.7193}

       l = 2.86 m

    Therefore, the length of the wire is 2.86 m

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