A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the mag

Question

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

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Ben Gia 6 months 2021-08-05T21:23:27+00:00 1 Answers 9 views 0

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    2021-08-05T21:25:21+00:00

    Question:

    A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

    (a)60 (b)90 (c)120

    Answer:

    (a)5.42 N (b)6.26 N (c)5.42 N

    Explanation:

    From the question

    Length of wire (L) = 2.80 m

    Current in wire (I) = 5.20 A

    Magnetic field (B) = 0.430 T

    Angle are different in each part.

    The magnetic force is given by

    F=I \times B \times L \times sin(\theta)

    So from data

    F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N

    Now sub parts

    (a)

    \theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N

    (b)

    \theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N

    (c)

    \theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N

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