(a) When a battery is connected to the plates of a 8.00-µF capacitor, it stores a charge of 48.0 µC. What is the voltage of the battery? V (

Question

(a) When a battery is connected to the plates of a 8.00-µF capacitor, it stores a charge of 48.0 µC. What is the voltage of the battery? V (b) If the same capacitor is connected to another battery and 192.0 µC of charge is stored on the capacitor, what is the voltage of the battery?

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Thu Nguyệt 1 year 2021-09-04T10:26:46+00:00 1 Answers 4 views 0

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    2021-09-04T10:27:53+00:00

    Answer:

    a.6 V

    b.24 V

    Explanation:

    We are given that

    a.[tex]C=8\mu F=8\times 10^{-6} F[/tex]

    [tex]1\mu =10^{-6} [/tex]

    Q=[tex]48\mu C=48\times 10^{-6} C[/tex]

    We know that

    [tex]V=\frac{Q}{C}[/tex]

    Using the formula

    [tex]V=\frac{48\times 10^{-6}}{8\times 10^{-6}}=6 V[/tex]

    b.[tex]Q=192\mu C=192\times 10^{-6} C[/tex]

    [tex]V=\frac{192\times 10^{-6}}{8\times 10^{-6}}=24 V[/tex]

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