A wheel rotating with a constant angular acceleration turns through 22 revolutions during a 5 s time interval. Its angular velocity at the e

Question

A wheel rotating with a constant angular acceleration turns through 22 revolutions during a 5 s time interval. Its angular velocity at the end of this interval is 12 rad/s. What is the angular acceleration of the wheel? Note that the initial angular velocity is not zero. Answer in units of rad/s 2 .

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Thành Đạt 2 weeks 2021-07-19T17:12:39+00:00 1 Answers 3 views 0

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    2021-07-19T17:14:08+00:00

    Answer:

    0.52rad/s^2

    Explanation:

    To find the angular acceleration you use the following formula:

    \omega^2=\omega_o^2+2\alpha\theta   (1)

    w: final angular velocity

    wo: initial angular velocity

    θ: revolutions

    α: angular acceleration

    you replace the values of the parameters in (1) and calculate α:

    \alpha=\frac{\omega^2-\omega_o^2}{2\theta}

    you use that θ=22 rev = 22(2π) = 44π

    \alpha=\frac{(12rad/s)^2-(0rad/s)^2}{2(44\pi)}=0.52\frac{rad}{s^2}

    hence, the angular acceñeration is 0.52rad/s^2

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