A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above the Earth’s surface. How muc

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A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above the Earth’s surface. How much would she weigh there

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Calantha 3 weeks 2021-08-31T14:56:08+00:00 1 Answers 0 views 0

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    2021-08-31T14:57:30+00:00

    Her weight at the height of R will be 100 N

    Explanation:

    The weight of the body on the surface of earth can be found by the relation

    W₁ = \frac{GMm}{R^2}                        I

    Here G is gravitational constant and M is the mass of earth .

    m is the mass of the body

    and R is the radius of earth  or the distance of body from the center of the earth .

    Now  she moves to height equal to R . Thus the distance from center of earth becomes 2 R .

    Thus Weight now is W₂ = \frac{GMm}{(2R)^2}                   II

    Dividing II by I , we have

    \frac{W_2}{W_1} = \frac{1}{4}

    But W₁ = 400 N

    Thus W₂ = \frac{400}{4} = 100 N

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