A water fountain jet shoots short spurts of water over a walkway. The water spurts reach a maximum​ height, then come down into a pond of wa

Question

A water fountain jet shoots short spurts of water over a walkway. The water spurts reach a maximum​ height, then come down into a pond of water on the other side of the walkway. The height above the​ jet, h, of a spurt of water t seconds after leaving the jet can be found by the function ​h(t)equalsminus16tsquaredplus16t. Find the time it takes for the spurt of water to return to the​ jet’s height; that​ is, when ​h(t)equals0.

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Eirian 6 mins 2021-07-22T17:14:45+00:00 1 Answers 0 views 0

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    2021-07-22T17:15:51+00:00

    Answer:

    The spurt of water takes 1 second to return to the​ jet’s height.

    Explanation:

    The height above the​ jet, h, of a spurt of water t seconds after leaving the jet can be given by the function ​as follows :

    h(t)=-16t^2+16t …….(1)

    We need to find the time it takes for the spurt of water to return to the​ jet’s height i.e. when h(t) = 0

    Equation (1) becomes :

    h(t)=0\\\\-16t^2+16t=0\\\\16t(-t+1)=0\\\\t=0,t=1

    So, the spurt of water takes 1 second to return to the​ jet’s height.

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