A volley ball is hit directly toward the ceiling in a gymnasium with a ceiling height of L 0 m. If the initial vertical velocity is 13 m/s a

Question

A volley ball is hit directly toward the ceiling in a gymnasium with a ceiling height of L 0 m. If the initial vertical velocity is 13 m/s and the release height is 1.8 m will the ball hit the ceiling?

in progress 0
Philomena 2 months 2021-09-02T05:04:17+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-02T05:05:34+00:00

    Complete Question:

    A volley ball is hit directly toward the ceiling in a gymnasium with a ceiling height of 10 m. If the initial vertical velocity is 13 m/s and the release height is 1.8 m will the ball hit the ceiling?

    Answer:

    The ball will hit the ceiling

    Explanation:

    Given;

    Initial vertical Velocity U = 13 m/s

    Height of the ceiling = 10 m

    Released height of the volley ball = 1.8 m

    Height traveled by the volley ball, is calculated as follows;

    V^2 =U^2 -2gH

    where;

    V is final vertical velocity

    2gH =U^2\\\\H = \frac{U^2}{2g} = \frac{(13)^2}{2(9.8)} = 8.62 m

    Remember this ball was released from 1.8 m height and it traveled 8.62 m.

    Total distance traveled = 1.8 + 8.62 = 10.42 m

    Therefore, the ball will hit the ceiling

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )