a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the wedge to keep

Question

a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the wedge to keep it horizontal .find weight of rod and reaction of wedge

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Thiên Hương 5 months 2021-08-11T10:02:44+00:00 1 Answers 26 views 0

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    2021-08-11T10:03:51+00:00

    Explanation:

    The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end.  The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.

    Sum the torques about the wedge (it may help to draw a diagram first).  Take counterclockwise to be positive.

    ∑τ = Iα

    W (0.25 m) − (100 N) (0.50 m) = 0

    W = 200 N

    Sum the forces in the y direction.

    ∑F = ma

    F − 100 N − 200 N = 0

    F = 300 N

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