A uniform magnetic field passes through a horizontal circular wire loop at an angle 17.3 ° 17.3° from the normal to the plane of the loop. T

Question

A uniform magnetic field passes through a horizontal circular wire loop at an angle 17.3 ° 17.3° from the normal to the plane of the loop. The magnitude of the magnetic field is 2.55 T 2.55 T , and the radius of the wire loop is 0.250 m 0.250 m . Find the magnetic flux Φ Φ through the loop.

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Kim Chi 6 months 2021-07-27T11:38:21+00:00 1 Answers 24 views 0

Answers ( )

    0
    2021-07-27T11:39:45+00:00

    Answer:

    4.78 × 10⁻³ T.m²

    Explanation:

    The expression for the magnetic flux is given by

    ∅ = BAcosФ

    where B = magnetic field strength

    A = Area of circular loop = πr²

    r = radius of the wire loop

    substitute πr² for A in the first equation

    ∅ = Bπr²cosФ

    ∅ = 2.55 × 3.14 × 0.025² × cos 17.3°

    ∅ = 4.78 × 10⁻³ T.m²

    OR

    0.00478 T.m²

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