A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1 ° from the normal to the plane of the loop. The mag

Question

A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1 ° from the normal to the plane of the loop. The magnitude of the magnetic field is 4.35 T , and the radius of the wire loop is 0.280 m . Find the magnetic flux Φ through the loop.

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Ben Gia 5 months 2021-08-28T11:01:11+00:00 1 Answers 2 views 0

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    2021-08-28T11:02:21+00:00

    Answer:

    Magnetic flux through the loop is 1.03 T m²

    Explanation:

    Given:

    Magnetic field, B = 4.35 T

    Radius of the circular loop, r = 0.280 m

    Angle between circular loop and magnetic field, θ = 15.1⁰

    Magnetic flux is determine by the relation:

    \Phi = BA\cos \theta   ….(1)

    Here A represents area of the circular loop.

    Area of circular loop, A = πr²

    Hence, the equation (1) becomes:

    \Phi=B\pi r^{2} \cos \theta

    Substitute the suitable values in the above equation.

    \Phi=4.35\times\pi (0.28)^{2} \cos 15.1

    \Phi = 1.03 T m²

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