A uniform electric field of magnitude 4.1 ✕ 105 n/c points in the positive x direction. find the change in electric potential energy of a +4

Question

A uniform electric field of magnitude 4.1 ✕ 105 n/c points in the positive x direction. find the change in electric potential energy of a +4.9 µc charge as it moves from the origin to each of the points given below.

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Khải Quang 4 years 2021-08-02T07:28:32+00:00 1 Answers 13 views 0

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  1. trungdung22
    0
    2021-08-02T07:30:23+00:00
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    Answer:

    2.009N

    Explanation:

    Force on a charge is equal to the product of the charge ans electric field intensity of the charge.

    F = qE

    q = 4.9E-6C

    E = 4.1E5 N/C

    F = qE

    F = 4.9E-6 * 4.1E5

    F = 2.009N

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