A. Una onda armónica que se propaga por un medio unidimensional tiene una frecuencia de 500Hz y una velocidad de propagación de 350m/s. ¿Qué

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A. Una onda armónica que se propaga por un medio unidimensional tiene una frecuencia de 500Hz y una velocidad de propagación de 350m/s. ¿Qué distancia mínima hay en un cierto instante, entre dos puntos del medio que oscilan con una diferencia de fase de π/3?

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Thành Công 1 year 2021-08-14T15:26:37+00:00 1 Answers 44 views 0

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    2021-08-14T15:28:04+00:00

    Answer:

    0.117 m

    Explanation:

    First of all, we can find the wavelength of the wave in the problem, by using the wave equation:

    [tex]v=f\lambda[/tex]

    where:

    v = 350 m/s is the speed of the wave

    f = 500 Hz is the frequency of the wave

    [tex]\lambda[/tex] is the wavelength

    Solving for [tex]\lambda[/tex],

    [tex]\lambda=\frac{v}{f}=\frac{350}{500}=0.7 m[/tex]

    This means that the distance between two consecutive points of the wave having a difference of phase of

    [tex]\phi=2\pi[/tex]

    is 0.7 m.

    Here we want to find the distance between two points that have a difference of phase of

    [tex]\phi’=\frac{\pi}{3}[/tex]

    So, we can set up the following rule of three:

    [tex]\frac{d}{\phi}=\frac{d’}{\phi’}[/tex]

    where d’ is the distance we are looking for. Solving for d’,

    [tex]d’=d\frac{\phi’}{\phi}=(0.7)\frac{\pi/3}{2\pi}=\frac{1}{6}(0.7)=0.117 m[/tex]

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