A typical atom has a diameter of about 1.32 x 10-10 m. A) What is this in inches? B) How many atoms are there along a 21.0cm lin

Question

A typical atom has a diameter of about 1.32 x 10-10 m.
A) What is this in inches?
B) How many atoms are there along a 21.0cm line?

in progress 0
Thạch Thảo 2 months 2021-07-30T06:22:47+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-30T06:24:39+00:00

    Answer:

    A) The value of the diameter in inches is 5.19685 × 10⁻⁹ inches

    B)  There are 1,590,909,091 atoms on a 21.0cm line

    Explanation:

    A) To determine what its diameter is in inches

    We will convert 1.32 × 10⁻¹⁰ m to inches

    First convert this to centimeters (cm)

    1.32 × 10⁻¹⁰m = 1.32 × 10⁻¹⁰ × 10² cm

    =  1.32 × 10⁻⁸cm

    Now, since 1 inch = 2.54 cm

    ∴ 1 cm = \frac{1}{2.54} inches

    If  1 cm = \frac{1}{2.54} inches

    Then 1.32 × 10⁻⁸ cm will be

    1.32 × 10⁻⁸ × \frac{1}{2.54} inches

    = 5.19685 × 10⁻⁹ inches

    This is the value of the diameter in inches

    B) For the number of atoms on a 21.0cm line

    The diameter of 1 atom is 1.32 × 10⁻¹⁰m

    1.32 × 10⁻¹⁰m = 1.32 × 10⁻⁸cm

    Hence, on a 21.0 cm line, we will have

    (21.0 / 1.32 × 10⁻⁸) atoms

    = 1590909091 atoms

    Hence, there are 1,590,909,091 atoms on a 21.0cm line

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )