A traveling electromagnetic wave in a vacuum has an electric field amplitude of 72.7 V/m. 72.7 V/m. Calculate the intensity S S of this wave

Question

A traveling electromagnetic wave in a vacuum has an electric field amplitude of 72.7 V/m. 72.7 V/m. Calculate the intensity S S of this wave. Then, determine the amount of energy U U that flows through area of 0.0211 m 2 0.0211 m2 over an interval of 10.3 s, 10.3 s, assuming that the area is perpendicular to the direction of wave propagation.

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Diễm Thu 2 weeks 2021-07-19T14:30:05+00:00 1 Answers 3 views 0

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    2021-07-19T14:31:46+00:00

    Answer:

    a) 7.02 W/m²

    b) 1.53 J

    Explanation:

    Given

    Amplitude of the electric wave, = 72.7 V/m

    Area of flow, A = 0.0211 m²

    Time taken, t = 10.3 s

    To calculate the Intensity, S. We use the formula

    I = E(rms)² / (cμ), where

    E(rms) = E / √2 = 72.7 / √2

    E(rms) = 72.7 / 1.4142

    E(rms) = 51.41

    c = 2.99*10^8

    μ = 1.26*10^-6

    I = 51.41² / [(2.99*10^8) (1.26 x 10^-6)]

    I = 2642.99 / 376.74

    I = 7.02 W/m²

    U = energy = IAt

    U = (7.02) * (0.0211) (10.3) J = 1.53 J

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