A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection

Question

A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident violet light (wavelength 400 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.

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Thành Công 5 months 2021-08-21T22:45:28+00:00 1 Answers 5 views 0

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    2021-08-21T22:46:51+00:00

    Answer:

    The thickness of the oil slick. t = 173.91 nm

    Explanation:

    Oil film thickness t is given by the equation

    t = \frac{\lambda}{2n}

    where λ = wavelength of incident light in air = 400 nm

    and n = index of refraction of oil

    therefore,

    t =\frac{400}{2\times 1.15}\\t= 173.91 nm

    The thickness of the oil slick. t = 173.91 nm

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